Base | Representation |
---|---|
bin | 10001100001100000101… |
… | …101001100011101100101 |
3 | 11021010021200210002022221 |
4 | 101201200231030131211 |
5 | 124212212101200031 |
6 | 2321112530152341 |
7 | 153000346121452 |
oct | 21414055143545 |
9 | 4233250702287 |
10 | 1204213303141 |
11 | 42478201a102 |
12 | 1754747226b1 |
13 | 897314708a4 |
14 | 423d9d24829 |
15 | 214cea46a11 |
hex | 11860b4c765 |
1204213303141 has 2 divisors, whose sum is σ = 1204213303142. Its totient is φ = 1204213303140.
The previous prime is 1204213303133. The next prime is 1204213303219. The reversal of 1204213303141 is 1413033124021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1009331669025 + 194881634116 = 1004655^2 + 441454^2 .
It is a cyclic number.
It is not a de Polignac number, because 1204213303141 - 23 = 1204213303133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1204213303541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 602106651570 + 602106651571.
It is an arithmetic number, because the mean of its divisors is an integer number (602106651571).
Almost surely, 21204213303141 is an apocalyptic number.
It is an amenable number.
1204213303141 is a deficient number, since it is larger than the sum of its proper divisors (1).
1204213303141 is an equidigital number, since it uses as much as digits as its factorization.
1204213303141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1204213303141 its reverse (1413033124021), we get a palindrome (2617246427162).
The spelling of 1204213303141 in words is "one trillion, two hundred four billion, two hundred thirteen million, three hundred three thousand, one hundred forty-one".
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