Base | Representation |
---|---|
bin | 11011011000010111110101… |
… | …010110001100101100101110 |
3 | 120210101020112012100000011222 |
4 | 123120113311112030230232 |
5 | 111240443442231040204 |
6 | 1104041053335343342 |
7 | 34236132152516666 |
oct | 3330276526145456 |
9 | 523336465300158 |
10 | 120422114315054 |
11 | 35408806150842 |
12 | 1160a742521b52 |
13 | 52269ab4a3426 |
14 | 21a466624d1a6 |
15 | ddc6c770dabe |
hex | 6d85f558cb2e |
120422114315054 has 8 divisors (see below), whose sum is σ = 180633334254840. Its totient is φ = 60211002896776.
The previous prime is 120422114315021. The next prime is 120422114315081. The reversal of 120422114315054 is 450513411224021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×1204221143150543 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24297044 + ... + 28830375.
It is an arithmetic number, because the mean of its divisors is an integer number (22579166781855).
Almost surely, 2120422114315054 is an apocalyptic number.
120422114315054 is a deficient number, since it is larger than the sum of its proper divisors (60211219939786).
120422114315054 is a wasteful number, since it uses less digits than its factorization.
120422114315054 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54260754.
The product of its (nonzero) digits is 38400, while the sum is 35.
Adding to 120422114315054 its reverse (450513411224021), we get a palindrome (570935525539075).
The spelling of 120422114315054 in words is "one hundred twenty trillion, four hundred twenty-two billion, one hundred fourteen million, three hundred fifteen thousand, fifty-four".
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