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12042244203533 is a prime number
BaseRepresentation
bin1010111100111100110110…
…1100000010010000001101
31120122020010200222222210022
42233033031230002100031
53034300004004003113
641340044113551525
72352011015555525
oct257171554022015
946566120888708
1012042244203533
1139230a5a04205
121425a4b2755a5
1369476a6ac71b
142d8bc2252685
1515d3a6956908
hexaf3cdb0240d

12042244203533 has 2 divisors, whose sum is σ = 12042244203534. Its totient is φ = 12042244203532.

The previous prime is 12042244203487. The next prime is 12042244203559. The reversal of 12042244203533 is 33530244224021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11717182303369 + 325061900164 = 3423037^2 + 570142^2 .

It is a cyclic number.

It is not a de Polignac number, because 12042244203533 - 210 = 12042244202509 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12042244203493 and 12042244203502.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12042244203133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6021122101766 + 6021122101767.

It is an arithmetic number, because the mean of its divisors is an integer number (6021122101767).

Almost surely, 212042244203533 is an apocalyptic number.

It is an amenable number.

12042244203533 is a deficient number, since it is larger than the sum of its proper divisors (1).

12042244203533 is an equidigital number, since it uses as much as digits as its factorization.

12042244203533 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 138240, while the sum is 35.

Adding to 12042244203533 its reverse (33530244224021), we get a palindrome (45572488427554).

The spelling of 12042244203533 in words is "twelve trillion, forty-two billion, two hundred forty-four million, two hundred three thousand, five hundred thirty-three".