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120422554113 = 340140851371
BaseRepresentation
bin111000000100110111…
…1100101101000000001
3102111211110021120202210
41300021233211220001
53433111133212423
6131153225132333
711462116551411
oct1601157455001
9374743246683
10120422554113
11470864352a4
121b40932a0a9
13b4818c47a4
145b854dc641
1531ec121b93
hex1c09be5a01

120422554113 has 4 divisors (see below), whose sum is σ = 160563405488. Its totient is φ = 80281702740.

The previous prime is 120422554111. The next prime is 120422554127. The reversal of 120422554113 is 311455224021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 120422554113 - 21 = 120422554111 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (120422554111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20070425683 + ... + 20070425688.

It is an arithmetic number, because the mean of its divisors is an integer number (40140851372).

Almost surely, 2120422554113 is an apocalyptic number.

It is an amenable number.

120422554113 is a deficient number, since it is larger than the sum of its proper divisors (40140851375).

120422554113 is an equidigital number, since it uses as much as digits as its factorization.

120422554113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40140851374.

The product of its (nonzero) digits is 9600, while the sum is 30.

Adding to 120422554113 its reverse (311455224021), we get a palindrome (431877778134).

The spelling of 120422554113 in words is "one hundred twenty billion, four hundred twenty-two million, five hundred fifty-four thousand, one hundred thirteen".

Divisors: 1 3 40140851371 120422554113