12042434113 has 4 divisors (see below), whose sum is σ = 12049837360. Its totient is φ = 12035030868.

The previous prime is 12042434071. The next prime is 12042434119. The reversal of 12042434113 is 31143424021.

12042434113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31143424021 = 47 ⋅662626043.

It is a cyclic number.

It is not a de Polignac number, because 12042434113 - 2¹³ = 12042425921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12042434119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3699183 + ... + 3702436.

It is an arithmetic number, because the mean of its divisors is an integer number (3012459340).

Almost surely, 2^12042434113 is an apocalyptic number.

It is an amenable number.

12042434113 is a deficient number, since it is larger than the sum of its proper divisors (7403247).

12042434113 is an equidigital number, since it uses as much as digits as its factorization.

12042434113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7403246.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 12042434113 its reverse (31143424021), we get a palindrome (43185858134).

The spelling of 12042434113 in words is "twelve billion, forty-two million, four hundred thirty-four thousand, one hundred thirteen".