Base | Representation |
---|---|
bin | 111000000100111011… |
… | …1000001100011110101 |
3 | 102111211120221121212211 |
4 | 1300021313001203311 |
5 | 3433112133103131 |
6 | 131153335013421 |
7 | 11462142251026 |
oct | 1601167014365 |
9 | 374746847784 |
10 | 120424503541 |
11 | 470875469a1 |
12 | 1b409b0a271 |
13 | b482127bb4 |
14 | 5b85888c4d |
15 | 31ec3a95b1 |
hex | 1c09dc18f5 |
120424503541 has 4 divisors (see below), whose sum is σ = 121029652000. Its totient is φ = 119819355084.
The previous prime is 120424503503. The next prime is 120424503601. The reversal of 120424503541 is 145305424021.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 120424503541 - 27 = 120424503413 is a prime.
It is a super-2 number, since 2×1204245035412 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120424500541) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 302573931 + ... + 302574328.
It is an arithmetic number, because the mean of its divisors is an integer number (30257413000).
Almost surely, 2120424503541 is an apocalyptic number.
It is an amenable number.
120424503541 is a deficient number, since it is larger than the sum of its proper divisors (605148459).
120424503541 is an equidigital number, since it uses as much as digits as its factorization.
120424503541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 605148458.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 120424503541 its reverse (145305424021), we get a palindrome (265729927562).
The spelling of 120424503541 in words is "one hundred twenty billion, four hundred twenty-four million, five hundred three thousand, five hundred forty-one".
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