Base | Representation |
---|---|
bin | 10110011011100111… |
… | …00010010010001111 |
3 | 1011002021121021202121 |
4 | 23031303202102033 |
5 | 144130422224042 |
6 | 5310554233411 |
7 | 604300613152 |
oct | 131563422217 |
9 | 34067537677 |
10 | 12042773647 |
11 | 511a9170a3 |
12 | 2401125867 |
13 | 119bc8c988 |
14 | 823593c99 |
15 | 4a73be367 |
hex | 2cdce248f |
12042773647 has 4 divisors (see below), whose sum is σ = 12051891376. Its totient is φ = 12033655920.
The previous prime is 12042773569. The next prime is 12042773651. The reversal of 12042773647 is 74637724021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12042773647 - 211 = 12042771599 is a prime.
It is a super-3 number, since 3×120427736473 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12042773447) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4556883 + ... + 4559524.
It is an arithmetic number, because the mean of its divisors is an integer number (3012972844).
Almost surely, 212042773647 is an apocalyptic number.
12042773647 is a deficient number, since it is larger than the sum of its proper divisors (9117729).
12042773647 is an equidigital number, since it uses as much as digits as its factorization.
12042773647 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9117728.
The product of its (nonzero) digits is 395136, while the sum is 43.
The spelling of 12042773647 in words is "twelve billion, forty-two million, seven hundred seventy-three thousand, six hundred forty-seven".
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