Base | Representation |
---|---|
bin | 1010111100111111101011… |
… | …0000011110011110010111 |
3 | 1120122022002101210211100101 |
4 | 2233033322300132132113 |
5 | 3034303031041424143 |
6 | 41340251124354531 |
7 | 2352035526623221 |
oct | 257177260363627 |
9 | 46568071724311 |
10 | 12043000342423 |
11 | 3923453807586 |
12 | 1426020545a47 |
13 | 69485b24649b |
14 | 2d8c54841411 |
15 | 15d3ed017b4d |
hex | af3fac1e797 |
12043000342423 has 2 divisors, whose sum is σ = 12043000342424. Its totient is φ = 12043000342422.
The previous prime is 12043000342409. The next prime is 12043000342447. The reversal of 12043000342423 is 32424300034021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12043000342423 - 25 = 12043000342391 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12043000342391 and 12043000342400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12043000342123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6021500171211 + 6021500171212.
It is an arithmetic number, because the mean of its divisors is an integer number (6021500171212).
Almost surely, 212043000342423 is an apocalyptic number.
12043000342423 is a deficient number, since it is larger than the sum of its proper divisors (1).
12043000342423 is an equidigital number, since it uses as much as digits as its factorization.
12043000342423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 28.
Adding to 12043000342423 its reverse (32424300034021), we get a palindrome (44467300376444).
The spelling of 12043000342423 in words is "twelve trillion, forty-three billion, three hundred forty-two thousand, four hundred twenty-three".
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