Base | Representation |
---|---|
bin | 10110011011101011… |
… | …00011010110111010 |
3 | 1011002022121010222110 |
4 | 23031311203112322 |
5 | 144131041133310 |
6 | 5311013433150 |
7 | 604305244413 |
oct | 131565432672 |
9 | 34068533873 |
10 | 12043302330 |
11 | 5120148324 |
12 | 240133b7b6 |
13 | 119c1164c7 |
14 | 82369080a |
15 | 4a7475d20 |
hex | 2cdd635ba |
12043302330 has 64 divisors (see below), whose sum is σ = 29108325888. Its totient is φ = 3188920320.
The previous prime is 12043302311. The next prime is 12043302347. The reversal of 12043302330 is 3320334021.
It is a super-2 number, since 2×120433023302 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12043302297 and 12043302306.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2574874 + ... + 2579546.
It is an arithmetic number, because the mean of its divisors is an integer number (454817592).
Almost surely, 212043302330 is an apocalyptic number.
12043302330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12043302330 is an abundant number, since it is smaller than the sum of its proper divisors (17065023558).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12043302330 is a wasteful number, since it uses less digits than its factorization.
12043302330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5271.
The product of its (nonzero) digits is 1296, while the sum is 21.
Adding to 12043302330 its reverse (3320334021), we get a palindrome (15363636351).
The spelling of 12043302330 in words is "twelve billion, forty-three million, three hundred two thousand, three hundred thirty".
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