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12043321141 is a prime number
BaseRepresentation
bin10110011011101011…
…00111111100110101
31011002022122002210011
423031311213330311
5144131042234031
65311014100221
7604305353305
oct131565477465
934068562704
1012043321141
115120160475
12240134a671
13119c121c37
14823697605
154a747b6b1
hex2cdd67f35

12043321141 has 2 divisors, whose sum is σ = 12043321142. Its totient is φ = 12043321140.

The previous prime is 12043321127. The next prime is 12043321151. The reversal of 12043321141 is 14112334021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6613105041 + 5430216100 = 81321^2 + 73690^2 .

It is a cyclic number.

It is not a de Polignac number, because 12043321141 - 27 = 12043321013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12043321151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6021660570 + 6021660571.

It is an arithmetic number, because the mean of its divisors is an integer number (6021660571).

Almost surely, 212043321141 is an apocalyptic number.

It is an amenable number.

12043321141 is a deficient number, since it is larger than the sum of its proper divisors (1).

12043321141 is an equidigital number, since it uses as much as digits as its factorization.

12043321141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 12043321141 its reverse (14112334021), we get a palindrome (26155655162).

The spelling of 12043321141 in words is "twelve billion, forty-three million, three hundred twenty-one thousand, one hundred forty-one".