Base | Representation |
---|---|
bin | 10001100001100111110… |
… | …010011011000110010011 |
3 | 11021010120222100022122002 |
4 | 101201213302123012103 |
5 | 124212433010124243 |
6 | 2321132412504215 |
7 | 153003321031652 |
oct | 21414762330623 |
9 | 4233528308562 |
10 | 1204332114323 |
11 | 424833099768 |
12 | 1754a847b06b |
13 | 8974cc6c670 |
14 | 4240ba11199 |
15 | 214da1b4eb8 |
hex | 11867c9b193 |
1204332114323 has 8 divisors (see below), whose sum is σ = 1296982360800. Its totient is φ = 1111683198528.
The previous prime is 1204332114319. The next prime is 1204332114341. The reversal of 1204332114323 is 3234112334021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1204332114323 - 22 = 1204332114319 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1204332114353) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2345858 + ... + 2812776.
It is an arithmetic number, because the mean of its divisors is an integer number (162122795100).
Almost surely, 21204332114323 is an apocalyptic number.
1204332114323 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1204332114323 is a deficient number, since it is larger than the sum of its proper divisors (92650246477).
1204332114323 is a wasteful number, since it uses less digits than its factorization.
1204332114323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 665341.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 1204332114323 its reverse (3234112334021), we get a palindrome (4438444448344).
The spelling of 1204332114323 in words is "one trillion, two hundred four billion, three hundred thirty-two million, one hundred fourteen thousand, three hundred twenty-three".
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