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12043340021 = 115110463371
BaseRepresentation
bin10110011011101011…
…01100100011110101
31011002022200001200102
423031311230203311
5144131043340041
65311014323445
7604305462326
oct131565544365
934068601612
1012043340021
115120173679
122401359585
13119c12a6cb
148236a044d
154a748209b
hex2cdd6c8f5

12043340021 has 4 divisors (see below), whose sum is σ = 12053804544. Its totient is φ = 12032875500.

The previous prime is 12043339969. The next prime is 12043340059. The reversal of 12043340021 is 12004334021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12043340021 - 210 = 12043338997 is a prime.

It is a super-2 number, since 2×120433400212 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12043339975 and 12043340002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12043340321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5230535 + ... + 5232836.

It is an arithmetic number, because the mean of its divisors is an integer number (3013451136).

Almost surely, 212043340021 is an apocalyptic number.

It is an amenable number.

12043340021 is a deficient number, since it is larger than the sum of its proper divisors (10464523).

12043340021 is a wasteful number, since it uses less digits than its factorization.

12043340021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10464522.

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 12043340021 its reverse (12004334021), we get a palindrome (24047674042).

The spelling of 12043340021 in words is "twelve billion, forty-three million, three hundred forty thousand, twenty-one".

Divisors: 1 1151 10463371 12043340021