Search a number
-
+
120433420113 = 3122849326779
BaseRepresentation
bin111000000101001100…
…1000010011101010001
3102111212012201122010020
41300022121002131101
53433121423420423
6131154254054053
711462311115616
oct1601231023521
9374765648106
10120433420113
1147091587066
121b410aaa329
13b483c2a586
145b86b2a50d
1531ed06b4e3
hex1c0a642751

120433420113 has 8 divisors (see below), whose sum is σ = 160579692000. Its totient is φ = 80288047488.

The previous prime is 120433420097. The next prime is 120433420123. The reversal of 120433420113 is 311024334021.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 120433420113 - 24 = 120433420097 is a prime.

It is a super-2 number, since 2×1204334201132 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (120433420123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 205158 + ... + 531936.

It is an arithmetic number, because the mean of its divisors is an integer number (20072461500).

Almost surely, 2120433420113 is an apocalyptic number.

It is an amenable number.

120433420113 is a deficient number, since it is larger than the sum of its proper divisors (40146271887).

120433420113 is a wasteful number, since it uses less digits than its factorization.

120433420113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 449631.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 120433420113 its reverse (311024334021), we get a palindrome (431457754134).

The spelling of 120433420113 in words is "one hundred twenty billion, four hundred thirty-three million, four hundred twenty thousand, one hundred thirteen".

Divisors: 1 3 122849 326779 368547 980337 40144473371 120433420113