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120434411231917 is a prime number
BaseRepresentation
bin11011011000100011010010…
…010011001101101010101101
3120210102102021012011002220021
4123120203102103031222231
5111241144133233410132
61104050445453122141
734240045660552366
oct3330432223155255
9523372235132807
10120434411231917
1135412a46470452
1211610bb4789351
135227bbacc65b3
1421a50b147ab6d
15ddcb9707e997
hex6d88d24cdaad

120434411231917 has 2 divisors, whose sum is σ = 120434411231918. Its totient is φ = 120434411231916.

The previous prime is 120434411231873. The next prime is 120434411231923. The reversal of 120434411231917 is 719132114434021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 118264885501156 + 2169525730761 = 10874966^2 + 1472931^2 .

It is a cyclic number.

It is not a de Polignac number, because 120434411231917 - 27 = 120434411231789 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120434411231977) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60217205615958 + 60217205615959.

It is an arithmetic number, because the mean of its divisors is an integer number (60217205615959).

Almost surely, 2120434411231917 is an apocalyptic number.

It is an amenable number.

120434411231917 is a deficient number, since it is larger than the sum of its proper divisors (1).

120434411231917 is an equidigital number, since it uses as much as digits as its factorization.

120434411231917 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 145152, while the sum is 43.

Adding to 120434411231917 its reverse (719132114434021), we get a palindrome (839566525665938).

The spelling of 120434411231917 in words is "one hundred twenty trillion, four hundred thirty-four billion, four hundred eleven million, two hundred thirty-one thousand, nine hundred seventeen".