120441044131 has 4 divisors (see below), whose sum is σ = 120741396264. Its totient is φ = 120140692000.

The previous prime is 120441044107. The next prime is 120441044161. The reversal of 120441044131 is 131440144021.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 131440144021 = 181 ⋅726188641.

It is a cyclic number.

It is not a de Polignac number, because 120441044131 - 2¹¹ = 120441042083 is a prime.

It is a super-2 number, since 2×120441044131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120441044096 and 120441044105.

It is not an unprimeable number, because it can be changed into a prime (120441044161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 150175465 + ... + 150176266.

It is an arithmetic number, because the mean of its divisors is an integer number (30185349066).

Almost surely, 2^120441044131 is an apocalyptic number.

120441044131 is a deficient number, since it is larger than the sum of its proper divisors (300352133).

120441044131 is an equidigital number, since it uses as much as digits as its factorization.

120441044131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 300352132.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 120441044131 its reverse (131440144021), we get a palindrome (251881188152).

The spelling of 120441044131 in words is "one hundred twenty billion, four hundred forty-one million, forty-four thousand, one hundred thirty-one".