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120442113241414 = 260221056620707
BaseRepresentation
bin11011011000101010011101…
…011000000011000101000110
3120210110011010221211201200021
4123120222131120003011012
5111241310421442211124
61104054202030005354
734240440562552516
oct3330523530030506
9523404127751607
10120442113241414
1135416239007158
12116125a404685a
135228847893473
1421a5602335846
15ddce983167e4
hex6d8a9d603146

120442113241414 has 4 divisors (see below), whose sum is σ = 180663169862124. Its totient is φ = 60221056620706.

The previous prime is 120442113241381. The next prime is 120442113241423. The reversal of 120442113241414 is 414142311244021.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 120442113241414.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30110528310352 + ... + 30110528310355.

It is an arithmetic number, because the mean of its divisors is an integer number (45165792465531).

Almost surely, 2120442113241414 is an apocalyptic number.

120442113241414 is a deficient number, since it is larger than the sum of its proper divisors (60221056620710).

120442113241414 is an equidigital number, since it uses as much as digits as its factorization.

120442113241414 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60221056620709.

The product of its (nonzero) digits is 24576, while the sum is 34.

Adding to 120442113241414 its reverse (414142311244021), we get a palindrome (534584424485435).

The spelling of 120442113241414 in words is "one hundred twenty trillion, four hundred forty-two billion, one hundred thirteen million, two hundred forty-one thousand, four hundred fourteen".

Divisors: 1 2 60221056620707 120442113241414