Base | Representation |
---|---|
bin | 1010111101000100001011… |
… | …1111010111001101110011 |
3 | 1120122102012212010210110102 |
4 | 2233101002333113031303 |
5 | 3034313021311020103 |
6 | 41341011255023015 |
7 | 2352110543364431 |
oct | 257210277271563 |
9 | 46572185123412 |
10 | 12044212204403 |
11 | 3923a15885405 |
12 | 14262ba36aa6b |
13 | 6949c2331b92 |
14 | 2d8d2b77bd51 |
15 | 15d46e5e7e88 |
hex | af442fd7373 |
12044212204403 has 4 divisors (see below), whose sum is σ = 12044220554520. Its totient is φ = 12044203854288.
The previous prime is 12044212204373. The next prime is 12044212204463. The reversal of 12044212204403 is 30440221244021.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 12044212204403 - 28 = 12044212204147 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12044212204463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1393925 + ... + 5102102.
It is an arithmetic number, because the mean of its divisors is an integer number (3011055138630).
Almost surely, 212044212204403 is an apocalyptic number.
12044212204403 is a deficient number, since it is larger than the sum of its proper divisors (8350117).
12044212204403 is an equidigital number, since it uses as much as digits as its factorization.
12044212204403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8350116.
The product of its (nonzero) digits is 12288, while the sum is 29.
Adding to 12044212204403 its reverse (30440221244021), we get a palindrome (42484433448424).
The spelling of 12044212204403 in words is "twelve trillion, forty-four billion, two hundred twelve million, two hundred four thousand, four hundred three".
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