Base | Representation |
---|---|
bin | 1010111101000100001111… |
… | …0010000001101010000111 |
3 | 1120122102020210010112121221 |
4 | 2233101003302001222013 |
5 | 3034313033211013242 |
6 | 41341012451421211 |
7 | 2352111064310611 |
oct | 257210362015207 |
9 | 46572223115557 |
10 | 12044225485447 |
11 | 3923a22326681 |
12 | 14263028b4807 |
13 | 6949c5001c9c |
14 | 2d8d2d437db1 |
15 | 15d47086d167 |
hex | af443c81a87 |
12044225485447 has 2 divisors, whose sum is σ = 12044225485448. Its totient is φ = 12044225485446.
The previous prime is 12044225485337. The next prime is 12044225485451. The reversal of 12044225485447 is 74458452244021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12044225485447 - 211 = 12044225483399 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12044225485394 and 12044225485403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12044225425447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6022112742723 + 6022112742724.
It is an arithmetic number, because the mean of its divisors is an integer number (6022112742724).
Almost surely, 212044225485447 is an apocalyptic number.
12044225485447 is a deficient number, since it is larger than the sum of its proper divisors (1).
12044225485447 is an equidigital number, since it uses as much as digits as its factorization.
12044225485447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11468800, while the sum is 52.
The spelling of 12044225485447 in words is "twelve trillion, forty-four billion, two hundred twenty-five million, four hundred eighty-five thousand, four hundred forty-seven".
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