Base | Representation |
---|---|
bin | 10110011011110011… |
… | …01111101010100001 |
3 | 1011002101122222111112 |
4 | 23031321233222201 |
5 | 144131331320223 |
6 | 5311053153105 |
7 | 604320502430 |
oct | 131571575241 |
9 | 34071588445 |
10 | 12044401313 |
11 | 5120828a7a |
12 | 240178b795 |
13 | 119c40c7a9 |
14 | 823899117 |
15 | 4a75e1778 |
hex | 2cde6faa1 |
12044401313 has 4 divisors (see below), whose sum is σ = 13765030080. Its totient is φ = 10323772548.
The previous prime is 12044401289. The next prime is 12044401333. The reversal of 12044401313 is 31310444021.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12044401313 - 224 = 12027624097 is a prime.
It is a super-2 number, since 2×120444013132 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12044401333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 860314373 + ... + 860314386.
It is an arithmetic number, because the mean of its divisors is an integer number (3441257520).
Almost surely, 212044401313 is an apocalyptic number.
It is an amenable number.
12044401313 is a deficient number, since it is larger than the sum of its proper divisors (1720628767).
12044401313 is an equidigital number, since it uses as much as digits as its factorization.
12044401313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1720628766.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 12044401313 its reverse (31310444021), we get a palindrome (43354845334).
The spelling of 12044401313 in words is "twelve billion, forty-four million, four hundred one thousand, three hundred thirteen".
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