Base | Representation |
---|---|
bin | 1010111101000101010011… |
… | …1011101110100000110111 |
3 | 1120122102222211121001020022 |
4 | 2233101110323232200313 |
5 | 3034314130342204033 |
6 | 41341101211155355 |
7 | 2352121160222525 |
oct | 257212473564067 |
9 | 46572884531208 |
10 | 12044513241143 |
11 | 392405a7a77a9 |
12 | 1426383145b5b |
13 | 694a3c803826 |
14 | 2d8d59741315 |
15 | 15d48ac5e098 |
hex | af454eee837 |
12044513241143 has 2 divisors, whose sum is σ = 12044513241144. Its totient is φ = 12044513241142.
The previous prime is 12044513241119. The next prime is 12044513241151. The reversal of 12044513241143 is 34114231544021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12044513241143 - 218 = 12044512978999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12044513241193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6022256620571 + 6022256620572.
It is an arithmetic number, because the mean of its divisors is an integer number (6022256620572).
Almost surely, 212044513241143 is an apocalyptic number.
12044513241143 is a deficient number, since it is larger than the sum of its proper divisors (1).
12044513241143 is an equidigital number, since it uses as much as digits as its factorization.
12044513241143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46080, while the sum is 35.
Adding to 12044513241143 its reverse (34114231544021), we get a palindrome (46158744785164).
The spelling of 12044513241143 in words is "twelve trillion, forty-four billion, five hundred thirteen million, two hundred forty-one thousand, one hundred forty-three".
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