Base | Representation |
---|---|
bin | 10110011011111011… |
… | …01101100010010101 |
3 | 1011002110121210220212 |
4 | 23031331231202111 |
5 | 144132113104143 |
6 | 5311131335205 |
7 | 604332363203 |
oct | 131575554225 |
9 | 34073553825 |
10 | 12045441173 |
11 | 5121379267 |
12 | 2401bb1505 |
13 | 119c6b4bac |
14 | 823a8a073 |
15 | 4a7749918 |
hex | 2cdf6d895 |
12045441173 has 2 divisors, whose sum is σ = 12045441174. Its totient is φ = 12045441172.
The previous prime is 12045441157. The next prime is 12045441211. The reversal of 12045441173 is 37114454021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8700785284 + 3344655889 = 93278^2 + 57833^2 .
It is an emirp because it is prime and its reverse (37114454021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12045441173 - 24 = 12045441157 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12045431173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6022720586 + 6022720587.
It is an arithmetic number, because the mean of its divisors is an integer number (6022720587).
Almost surely, 212045441173 is an apocalyptic number.
It is an amenable number.
12045441173 is a deficient number, since it is larger than the sum of its proper divisors (1).
12045441173 is an equidigital number, since it uses as much as digits as its factorization.
12045441173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13440, while the sum is 32.
Adding to 12045441173 its reverse (37114454021), we get a palindrome (49159895194).
The spelling of 12045441173 in words is "twelve billion, forty-five million, four hundred forty-one thousand, one hundred seventy-three".
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