Base | Representation |
---|---|
bin | 10001100010001111110… |
… | …011101111110100111101 |
3 | 11021012022202202210020121 |
4 | 101202033303233310331 |
5 | 124220321402100023 |
6 | 2321323200014541 |
7 | 153026053114264 |
oct | 21421763576475 |
9 | 4235282683217 |
10 | 1205003550013 |
11 | 4250480a929a |
12 | 175655301451 |
13 | 898290ba3a3 |
14 | 42472c715db |
15 | 215290e3d5d |
hex | 1188fcefd3d |
1205003550013 has 2 divisors, whose sum is σ = 1205003550014. Its totient is φ = 1205003550012.
The previous prime is 1205003550007. The next prime is 1205003550017. The reversal of 1205003550013 is 3100553005021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1169464890724 + 35538659289 = 1081418^2 + 188517^2 .
It is a cyclic number.
It is not a de Polignac number, because 1205003550013 - 213 = 1205003541821 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1205003550013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1205003550017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 602501775006 + 602501775007.
It is an arithmetic number, because the mean of its divisors is an integer number (602501775007).
Almost surely, 21205003550013 is an apocalyptic number.
It is an amenable number.
1205003550013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1205003550013 is an equidigital number, since it uses as much as digits as its factorization.
1205003550013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2250, while the sum is 25.
Adding to 1205003550013 its reverse (3100553005021), we get a palindrome (4305556555034).
The spelling of 1205003550013 in words is "one trillion, two hundred five billion, three million, five hundred fifty thousand, thirteen".
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