Base | Representation |
---|---|
bin | 11011011001100011010010… |
… | …111100000000101011010111 |
3 | 120210122222200010002120110020 |
4 | 123121203102330000223113 |
5 | 111243310413144401401 |
6 | 1104142213503200223 |
7 | 34245031115433060 |
oct | 3331432274005327 |
9 | 523588603076406 |
10 | 120503141403351 |
11 | 3543a1058a2523 |
12 | 116223962a6073 |
13 | 523152233aca5 |
14 | 21a8551587567 |
15 | dde86ae5ed36 |
hex | 6d98d2f00ad7 |
120503141403351 has 16 divisors (see below), whose sum is σ = 191607479499264. Its totient is φ = 65865071077344.
The previous prime is 120503141403347. The next prime is 120503141403377. The reversal of 120503141403351 is 153304141305021.
120503141403351 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 120503141403351 - 22 = 120503141403347 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120503141403311) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 124744452316 + ... + 124744453281.
It is an arithmetic number, because the mean of its divisors is an integer number (11975467468704).
Almost surely, 2120503141403351 is an apocalyptic number.
120503141403351 is a deficient number, since it is larger than the sum of its proper divisors (71104338095913).
120503141403351 is a wasteful number, since it uses less digits than its factorization.
120503141403351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 249488905630.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 120503141403351 its reverse (153304141305021), we get a palindrome (273807282708372).
The spelling of 120503141403351 in words is "one hundred twenty trillion, five hundred three billion, one hundred forty-one million, four hundred three thousand, three hundred fifty-one".
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