Base | Representation |
---|---|
bin | 1010111101011011000010… |
… | …0010111110010010001011 |
3 | 1120200000001021111102202201 |
4 | 2233112300202332102023 |
5 | 3034413101334121212 |
6 | 41343504022541031 |
7 | 2352415534236136 |
oct | 257266042762213 |
9 | 46600037442681 |
10 | 12050345223307 |
11 | 39265827aa276 |
12 | 1427530297777 |
13 | 69545bb32551 |
14 | 2d93500d521d |
15 | 15d6ccc58b57 |
hex | af5b08be48b |
12050345223307 has 2 divisors, whose sum is σ = 12050345223308. Its totient is φ = 12050345223306.
The previous prime is 12050345223263. The next prime is 12050345223337. The reversal of 12050345223307 is 70332254305021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12050345223307 is a prime.
It is not a weakly prime, because it can be changed into another prime (12050345223337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6025172611653 + 6025172611654.
It is an arithmetic number, because the mean of its divisors is an integer number (6025172611654).
Almost surely, 212050345223307 is an apocalyptic number.
12050345223307 is a deficient number, since it is larger than the sum of its proper divisors (1).
12050345223307 is an equidigital number, since it uses as much as digits as its factorization.
12050345223307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 151200, while the sum is 37.
Adding to 12050345223307 its reverse (70332254305021), we get a palindrome (82382599528328).
The spelling of 12050345223307 in words is "twelve trillion, fifty billion, three hundred forty-five million, two hundred twenty-three thousand, three hundred seven".
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