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12052433 is a prime number
BaseRepresentation
bin101101111110…
…011111010001
3211200022211102
4231332133101
511041134213
61110154145
7204305201
oct55763721
924608742
1012052433
116892198
124052955
13265cb23
14185a401
1510d1158
hexb7e7d1

12052433 has 2 divisors, whose sum is σ = 12052434. Its totient is φ = 12052432.

The previous prime is 12052423. The next prime is 12052471. The reversal of 12052433 is 33425021.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7524049 + 4528384 = 2743^2 + 2128^2 .

It is a cyclic number.

It is not a de Polignac number, because 12052433 - 210 = 12051409 is a prime.

It is a super-2 number, since 2×120524332 = 290522282438978, which contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (12052423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6026216 + 6026217.

It is an arithmetic number, because the mean of its divisors is an integer number (6026217).

Almost surely, 212052433 is an apocalyptic number.

It is an amenable number.

12052433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12052433 is an equidigital number, since it uses as much as digits as its factorization.

12052433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 20.

The square root of 12052433 is about 3471.6614178229. The cubic root of 12052433 is about 229.2758129264.

Adding to 12052433 its reverse (33425021), we get a palindrome (45477454).

The spelling of 12052433 in words is "twelve million, fifty-two thousand, four hundred thirty-three".