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12054073153 = 64171187843
BaseRepresentation
bin10110011100111101…
…01000111101000001
31011010001212100202211
423032132220331001
5144141320320103
65312040342121
7604465634263
oct131636507501
934101770684
1012054073153
115126234631
122404a74941
1311a1417b85
14824c95b33
154a83a236d
hex2ce7a8f41

12054073153 has 4 divisors (see below), whose sum is σ = 12054325168. Its totient is φ = 12053821140.

The previous prime is 12054073133. The next prime is 12054073181. The reversal of 12054073153 is 35137045021.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12054073153 - 25 = 12054073121 is a prime.

It is a super-2 number, since 2×120540731532 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12054073133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29751 + ... + 158092.

It is an arithmetic number, because the mean of its divisors is an integer number (3013581292).

Almost surely, 212054073153 is an apocalyptic number.

It is an amenable number.

12054073153 is a deficient number, since it is larger than the sum of its proper divisors (252015).

12054073153 is an equidigital number, since it uses as much as digits as its factorization.

12054073153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 252014.

The product of its (nonzero) digits is 12600, while the sum is 31.

The spelling of 12054073153 in words is "twelve billion, fifty-four million, seventy-three thousand, one hundred fifty-three".

Divisors: 1 64171 187843 12054073153