Base | Representation |
---|---|
bin | 1010111101101001001101… |
… | …1010011110000001100011 |
3 | 1120200100212112112100212120 |
4 | 2233122103122132001203 |
5 | 3034443400231001201 |
6 | 41345333430555323 |
7 | 2352612052343364 |
oct | 257322332360143 |
9 | 46610775470776 |
10 | 12054151422051 |
11 | 3928156254772 |
12 | 1428212b08b43 |
13 | 69591755a25b |
14 | 2d95d17dbb6b |
15 | 15d851e9b536 |
hex | af69369e063 |
12054151422051 has 8 divisors (see below), whose sum is σ = 16072225488144. Its totient is φ = 8036089152000.
The previous prime is 12054151422043. The next prime is 12054151422107. The reversal of 12054151422051 is 15022415145021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12054151422051 - 23 = 12054151422043 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12054151422011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 198006 + ... + 4914011.
It is an arithmetic number, because the mean of its divisors is an integer number (2009028186018).
Almost surely, 212054151422051 is an apocalyptic number.
12054151422051 is a deficient number, since it is larger than the sum of its proper divisors (4018074066093).
12054151422051 is an equidigital number, since it uses as much as digits as its factorization.
12054151422051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5898021.
The product of its (nonzero) digits is 16000, while the sum is 33.
Adding to 12054151422051 its reverse (15022415145021), we get a palindrome (27076566567072).
The spelling of 12054151422051 in words is "twelve trillion, fifty-four billion, one hundred fifty-one million, four hundred twenty-two thousand, fifty-one".
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