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120556489793 is a prime number
BaseRepresentation
bin111000001000110111…
…0100000110001000001
3102112011210022012222112
41300101232200301001
53433344430133133
6131214411545105
711465334153425
oct1602156406101
9375153265875
10120556489793
1147144aa5143
121b44615b195
13b4a358a77c
145b99204b85
153208c7b648
hex1c11ba0c41

120556489793 has 2 divisors, whose sum is σ = 120556489794. Its totient is φ = 120556489792.

The previous prime is 120556489751. The next prime is 120556489819. The reversal of 120556489793 is 397984655021.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 116804682289 + 3751807504 = 341767^2 + 61252^2 .

It is an emirp because it is prime and its reverse (397984655021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 120556489793 - 212 = 120556485697 is a prime.

It is not a weakly prime, because it can be changed into another prime (120556482793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60278244896 + 60278244897.

It is an arithmetic number, because the mean of its divisors is an integer number (60278244897).

It is a 1-persistent number, because it is pandigital, but 2⋅120556489793 = 241112979586 is not.

Almost surely, 2120556489793 is an apocalyptic number.

It is an amenable number.

120556489793 is a deficient number, since it is larger than the sum of its proper divisors (1).

120556489793 is an equidigital number, since it uses as much as digits as its factorization.

120556489793 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16329600, while the sum is 59.

The spelling of 120556489793 in words is "one hundred twenty billion, five hundred fifty-six million, four hundred eighty-nine thousand, seven hundred ninety-three".