Base | Representation |
---|---|
bin | 11011011010100011100100… |
… | …000110101010101100001011 |
3 | 120210220120210100211220212102 |
4 | 123122203210012222230023 |
5 | 111300423230103330113 |
6 | 1104234025221104015 |
7 | 34253023151366003 |
oct | 3332434406525413 |
9 | 523816710756772 |
10 | 120572148886283 |
11 | 354663a7811856 |
12 | 1163383485800b |
13 | 5237b9bc68423 |
14 | 21aba1a43d003 |
15 | de155936b758 |
hex | 6da8e41aab0b |
120572148886283 has 2 divisors, whose sum is σ = 120572148886284. Its totient is φ = 120572148886282.
The previous prime is 120572148886213. The next prime is 120572148886349. The reversal of 120572148886283 is 382688841275021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120572148886283 - 28 = 120572148886027 is a prime.
It is not a weakly prime, because it can be changed into another prime (120572148886213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60286074443141 + 60286074443142.
It is an arithmetic number, because the mean of its divisors is an integer number (60286074443142).
Almost surely, 2120572148886283 is an apocalyptic number.
120572148886283 is a deficient number, since it is larger than the sum of its proper divisors (1).
120572148886283 is an equidigital number, since it uses as much as digits as its factorization.
120572148886283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 82575360, while the sum is 65.
The spelling of 120572148886283 in words is "one hundred twenty trillion, five hundred seventy-two billion, one hundred forty-eight million, eight hundred eighty-six thousand, two hundred eighty-three".
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