Base | Representation |
---|---|
bin | 1010111110001100001000… |
… | …0110000000110001111101 |
3 | 1120201021001202200020100111 |
4 | 2233203002012000301331 |
5 | 3040122044234220013 |
6 | 41353523501030021 |
7 | 2353363245364606 |
oct | 257430206006175 |
9 | 46637052606314 |
10 | 12063524523133 |
11 | 39311261092a6 |
12 | 1429ba9b55311 |
13 | 69677c3c1505 |
14 | 2d9c405b4dad |
15 | 15dbeecc673d |
hex | af8c2180c7d |
12063524523133 has 2 divisors, whose sum is σ = 12063524523134. Its totient is φ = 12063524523132.
The previous prime is 12063524523103. The next prime is 12063524523151. The reversal of 12063524523133 is 33132542536021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11196432055449 + 867092467684 = 3346107^2 + 931178^2 .
It is a cyclic number.
It is not a de Polignac number, because 12063524523133 - 225 = 12063490968701 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12063524523103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6031762261566 + 6031762261567.
It is an arithmetic number, because the mean of its divisors is an integer number (6031762261567).
Almost surely, 212063524523133 is an apocalyptic number.
It is an amenable number.
12063524523133 is a deficient number, since it is larger than the sum of its proper divisors (1).
12063524523133 is an equidigital number, since it uses as much as digits as its factorization.
12063524523133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 388800, while the sum is 40.
The spelling of 12063524523133 in words is "twelve trillion, sixty-three billion, five hundred twenty-four million, five hundred twenty-three thousand, one hundred thirty-three".
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