120645414531511 has 4 divisors (see below), whose sum is σ = 120654418606000. Its totient is φ = 120636410457024.

The previous prime is 120645414531493. The next prime is 120645414531569. The reversal of 120645414531511 is 115135414546021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120645414531511 - 2¹¹ = 120645414529463 is a prime.

It is a super-3 number, since 3×120645414531511³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120645414531571) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4502017146 + ... + 4502043943.

It is an arithmetic number, because the mean of its divisors is an integer number (30163604651500).

Almost surely, 2^{120645414531511} is an apocalyptic number.

120645414531511 is a deficient number, since it is larger than the sum of its proper divisors (9004074489).

120645414531511 is an equidigital number, since it uses as much as digits as its factorization.

120645414531511 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9004074488.

The product of its (nonzero) digits is 288000, while the sum is 43.

The spelling of 120645414531511 in words is "one hundred twenty trillion, six hundred forty-five billion, four hundred fourteen million, five hundred thirty-one thousand, five hundred eleven".