Base | Representation |
---|---|
bin | 1011000000010100000000… |
… | …1100111100111101000011 |
3 | 1120211202012210201221211102 |
4 | 2300011000030330331003 |
5 | 3041221300000310201 |
6 | 41422355133205015 |
7 | 2356124165042222 |
oct | 260050014747503 |
9 | 46752183657742 |
10 | 12100000010051 |
11 | 3945643617508 |
12 | 143508963076b |
13 | 69a043203a75 |
14 | 2db900a42cb9 |
15 | 15eb3715d26b |
hex | b014033cf43 |
12100000010051 has 2 divisors, whose sum is σ = 12100000010052. Its totient is φ = 12100000010050.
The previous prime is 12100000009969. The next prime is 12100000010171. The reversal of 12100000010051 is 15001000000121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12100000010051 - 238 = 11825122103107 is a prime.
It is not a weakly prime, because it can be changed into another prime (12100000013051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050000005025 + 6050000005026.
It is an arithmetic number, because the mean of its divisors is an integer number (6050000005026).
Almost surely, 212100000010051 is an apocalyptic number.
12100000010051 is a deficient number, since it is larger than the sum of its proper divisors (1).
12100000010051 is an equidigital number, since it uses as much as digits as its factorization.
12100000010051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10, while the sum is 11.
Adding to 12100000010051 its reverse (15001000000121), we get a palindrome (27101000010172).
The spelling of 12100000010051 in words is "twelve trillion, one hundred billion, ten thousand, fifty-one".
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