121000000213 has 2 divisors, whose sum is σ = 121000000214. Its totient is φ = 121000000212.

The previous prime is 121000000201. The next prime is 121000000283. The reversal of 121000000213 is 312000000121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 103000557969 + 17999442244 = 320937^2 + 134162^2 .

It is an emirp because it is prime and its reverse (312000000121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121000000213 - 2⁵ = 121000000181 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 121000000213.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121000000283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60500000106 + 60500000107.

It is an arithmetic number, because the mean of its divisors is an integer number (60500000107).

Almost surely, 2^121000000213 is an apocalyptic number.

It is an amenable number.

121000000213 is a deficient number, since it is larger than the sum of its proper divisors (1).

121000000213 is an equidigital number, since it uses as much as digits as its factorization.

121000000213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 10.

Adding to 121000000213 its reverse (312000000121), we get a palindrome (433000000334).

The spelling of 121000000213 in words is "one hundred twenty-one billion, two hundred thirteen", and thus it is an aban number.