Base | Representation |
---|---|
bin | 11011100000110010001001… |
… | …001111001001110110001111 |
3 | 120212102111110111002200121011 |
4 | 123200302021033021312033 |
5 | 111324431222001121444 |
6 | 1105202404355150051 |
7 | 34325653541324221 |
oct | 3340621117116617 |
9 | 525374414080534 |
10 | 121000121113999 |
11 | 356109549a1916 |
12 | 116a27738a5327 |
13 | 526935481c4aa |
14 | 21c4619602411 |
15 | dec756842734 |
hex | 6e0c893c9d8f |
121000121113999 has 2 divisors, whose sum is σ = 121000121114000. Its totient is φ = 121000121113998.
The previous prime is 121000121113961. The next prime is 121000121114023. The reversal of 121000121113999 is 999311121000121.
It is a strong prime.
It is an emirp because it is prime and its reverse (999311121000121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 121000121113999 - 243 = 112204028091791 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121000121113909) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60500060556999 + 60500060557000.
It is an arithmetic number, because the mean of its divisors is an integer number (60500060557000).
Almost surely, 2121000121113999 is an apocalyptic number.
121000121113999 is a deficient number, since it is larger than the sum of its proper divisors (1).
121000121113999 is an equidigital number, since it uses as much as digits as its factorization.
121000121113999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8748, while the sum is 40.
The spelling of 121000121113999 in words is "one hundred twenty-one trillion, one hundred twenty-one million, one hundred thirteen thousand, nine hundred ninety-nine".
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