Base | Representation |
---|---|
bin | 1011000000010100000110… |
… | …0000110101100111110001 |
3 | 1120211202021100010011112011 |
4 | 2300011001200311213301 |
5 | 3041221321113000423 |
6 | 41422401240402521 |
7 | 2356124553000205 |
oct | 260050140654761 |
9 | 46752240104464 |
10 | 12100022000113 |
11 | 3945654a76a13 |
12 | 1435094a76441 |
13 | 69a047932c38 |
14 | 2db903928b05 |
15 | 15eb39053b0d |
hex | b01418359f1 |
12100022000113 has 2 divisors, whose sum is σ = 12100022000114. Its totient is φ = 12100022000112.
The previous prime is 12100022000093. The next prime is 12100022000123. The reversal of 12100022000113 is 31100022000121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10167788557809 + 1932233442304 = 3188697^2 + 1390048^2 .
It is a cyclic number.
It is not a de Polignac number, because 12100022000113 - 29 = 12100021999601 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12100022000093 and 12100022000102.
It is not a weakly prime, because it can be changed into another prime (12100022000123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050011000056 + 6050011000057.
It is an arithmetic number, because the mean of its divisors is an integer number (6050011000057).
Almost surely, 212100022000113 is an apocalyptic number.
It is an amenable number.
12100022000113 is a deficient number, since it is larger than the sum of its proper divisors (1).
12100022000113 is an equidigital number, since it uses as much as digits as its factorization.
12100022000113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 12100022000113 its reverse (31100022000121), we get a palindrome (43200044000234).
The spelling of 12100022000113 in words is "twelve trillion, one hundred billion, twenty-two million, one hundred thirteen", and thus it is an aban number.
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