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12100022000113 is a prime number
BaseRepresentation
bin1011000000010100000110…
…0000110101100111110001
31120211202021100010011112011
42300011001200311213301
53041221321113000423
641422401240402521
72356124553000205
oct260050140654761
946752240104464
1012100022000113
113945654a76a13
121435094a76441
1369a047932c38
142db903928b05
1515eb39053b0d
hexb01418359f1

12100022000113 has 2 divisors, whose sum is σ = 12100022000114. Its totient is φ = 12100022000112.

The previous prime is 12100022000093. The next prime is 12100022000123. The reversal of 12100022000113 is 31100022000121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10167788557809 + 1932233442304 = 3188697^2 + 1390048^2 .

It is a cyclic number.

It is not a de Polignac number, because 12100022000113 - 29 = 12100021999601 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12100022000093 and 12100022000102.

It is not a weakly prime, because it can be changed into another prime (12100022000123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050011000056 + 6050011000057.

It is an arithmetic number, because the mean of its divisors is an integer number (6050011000057).

Almost surely, 212100022000113 is an apocalyptic number.

It is an amenable number.

12100022000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12100022000113 is an equidigital number, since it uses as much as digits as its factorization.

12100022000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 12100022000113 its reverse (31100022000121), we get a palindrome (43200044000234).

The spelling of 12100022000113 in words is "twelve trillion, one hundred billion, twenty-two million, one hundred thirteen", and thus it is an aban number.