Base | Representation |
---|---|
bin | 10001100110111001110… |
… | …011101011011010100111 |
3 | 11021200020012101101112201 |
4 | 101212321303223122213 |
5 | 124311041301023221 |
6 | 2323511234355331 |
7 | 153264002003155 |
oct | 21467163533247 |
9 | 4250205341481 |
10 | 1210003142311 |
11 | 427183257a57 |
12 | 17660b72bb47 |
13 | 8a144b35522 |
14 | 427c8c683d5 |
15 | 2171ceb9891 |
hex | 119b9ceb6a7 |
1210003142311 has 2 divisors, whose sum is σ = 1210003142312. Its totient is φ = 1210003142310.
The previous prime is 1210003142297. The next prime is 1210003142333. The reversal of 1210003142311 is 1132413000121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1210003142311 - 235 = 1175643403943 is a prime.
It is a super-4 number, since 4×12100031423114 (a number of 49 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1210003142111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605001571155 + 605001571156.
It is an arithmetic number, because the mean of its divisors is an integer number (605001571156).
Almost surely, 21210003142311 is an apocalyptic number.
1210003142311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1210003142311 is an equidigital number, since it uses as much as digits as its factorization.
1210003142311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1210003142311 its reverse (1132413000121), we get a palindrome (2342416142432).
The spelling of 1210003142311 in words is "one trillion, two hundred ten billion, three million, one hundred forty-two thousand, three hundred eleven".
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