Base | Representation |
---|---|
bin | 111000010110000110… |
… | …0011110001101111101 |
3 | 102120022201212212211202 |
4 | 1300230030132031331 |
5 | 3440302120120133 |
6 | 131330433425245 |
7 | 11512335500366 |
oct | 1605414361575 |
9 | 376281785752 |
10 | 121000551293 |
11 | 47352725116 |
12 | 1b54aa0b225 |
13 | b54458845b |
14 | 5bdc198b6d |
15 | 3232c452e8 |
hex | 1c2c31e37d |
121000551293 has 2 divisors, whose sum is σ = 121000551294. Its totient is φ = 121000551292.
The previous prime is 121000551283. The next prime is 121000551359. The reversal of 121000551293 is 392155000121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 68587943449 + 52412607844 = 261893^2 + 228938^2 .
It is a cyclic number.
It is not a de Polignac number, because 121000551293 - 210 = 121000550269 is a prime.
It is a super-2 number, since 2×1210005512932 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121000551283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60500275646 + 60500275647.
It is an arithmetic number, because the mean of its divisors is an integer number (60500275647).
Almost surely, 2121000551293 is an apocalyptic number.
It is an amenable number.
121000551293 is a deficient number, since it is larger than the sum of its proper divisors (1).
121000551293 is an equidigital number, since it uses as much as digits as its factorization.
121000551293 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2700, while the sum is 29.
The spelling of 121000551293 in words is "one hundred twenty-one billion, five hundred fifty-one thousand, two hundred ninety-three".
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