Base | Representation |
---|---|
bin | 1011000000010100011000… |
… | …1110101010100000110111 |
3 | 1120211202110211222222111020 |
4 | 2300011012032222200313 |
5 | 3041222001341401403 |
6 | 41422413144312223 |
7 | 2356126533345441 |
oct | 260050616524067 |
9 | 46752424888436 |
10 | 12100101122103 |
11 | 39456956a8495 |
12 | 14350b7472673 |
13 | 69a05b146797 |
14 | 2db910243491 |
15 | 15eb40e82453 |
hex | b01463aa837 |
12100101122103 has 4 divisors (see below), whose sum is σ = 16133468162808. Its totient is φ = 8066734081400.
The previous prime is 12100101122099. The next prime is 12100101122117. The reversal of 12100101122103 is 30122110100121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12100101122103 - 22 = 12100101122099 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12100101122803) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2016683520348 + ... + 2016683520353.
It is an arithmetic number, because the mean of its divisors is an integer number (4033367040702).
Almost surely, 212100101122103 is an apocalyptic number.
12100101122103 is a deficient number, since it is larger than the sum of its proper divisors (4033367040705).
12100101122103 is an equidigital number, since it uses as much as digits as its factorization.
12100101122103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4033367040704.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 12100101122103 its reverse (30122110100121), we get a palindrome (42222211222224).
The spelling of 12100101122103 in words is "twelve trillion, one hundred billion, one hundred one million, one hundred twenty-two thousand, one hundred three".
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