Base | Representation |
---|---|
bin | 10001100110111010010… |
… | …010000111011010011101 |
3 | 11021200020202101202200011 |
4 | 101212322102013122131 |
5 | 124311100321340214 |
6 | 2323512121403221 |
7 | 153264126554434 |
oct | 21467222073235 |
9 | 4250222352604 |
10 | 1210011121309 |
11 | 427187807771 |
12 | 176612339511 |
13 | 8a14669a223 |
14 | 427c9d4411b |
15 | 2171da43ac4 |
hex | 119ba48769d |
1210011121309 has 2 divisors, whose sum is σ = 1210011121310. Its totient is φ = 1210011121308.
The previous prime is 1210011121219. The next prime is 1210011121343. The reversal of 1210011121309 is 9031211100121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 931012712100 + 278998409209 = 964890^2 + 528203^2 .
It is a cyclic number.
It is not a de Polignac number, because 1210011121309 - 29 = 1210011120797 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1210011121309.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1210111121309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605005560654 + 605005560655.
It is an arithmetic number, because the mean of its divisors is an integer number (605005560655).
Almost surely, 21210011121309 is an apocalyptic number.
It is an amenable number.
1210011121309 is a deficient number, since it is larger than the sum of its proper divisors (1).
1210011121309 is an equidigital number, since it uses as much as digits as its factorization.
1210011121309 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 22.
The spelling of 1210011121309 in words is "one trillion, two hundred ten billion, eleven million, one hundred twenty-one thousand, three hundred nine".
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