Base | Representation |
---|---|
bin | 11011100000110011010111… |
… | …011100011110111111000111 |
3 | 120212102121211221002011011100 |
4 | 123200303113130132333013 |
5 | 111324441413401400203 |
6 | 1105203142510311143 |
7 | 34326031213203132 |
oct | 3340632734367707 |
9 | 525377757064140 |
10 | 121001433231303 |
11 | 35611468615a89 |
12 | 116a2a7b1b84b3 |
13 | 526950360a971 |
14 | 21c4701999219 |
15 | dec7d1b27ea3 |
hex | 6e0cd771efc7 |
121001433231303 has 12 divisors (see below), whose sum is σ = 174780424244920. Its totient is φ = 80667356195376.
The previous prime is 121001433231247. The next prime is 121001433231323. The reversal of 121001433231303 is 303132334100121.
121001433231303 is a `hidden beast` number, since 1 + 2 + 1 + 0 + 0 + 14 + 332 + 313 + 0 + 3 = 666.
It is not a de Polignac number, because 121001433231303 - 28 = 121001433231047 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121001433231323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 19261813 + ... + 24759246.
Almost surely, 2121001433231303 is an apocalyptic number.
121001433231303 is a deficient number, since it is larger than the sum of its proper divisors (53778991013617).
121001433231303 is a wasteful number, since it uses less digits than its factorization.
121001433231303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 44326478 (or 44326475 counting only the distinct ones).
The product of its (nonzero) digits is 3888, while the sum is 27.
Adding to 121001433231303 its reverse (303132334100121), we get a palindrome (424133767331424).
The spelling of 121001433231303 in words is "one hundred twenty-one trillion, one billion, four hundred thirty-three million, two hundred thirty-one thousand, three hundred three".
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