Base | Representation |
---|---|
bin | 10110100010011100… |
… | …11000100100110100 |
3 | 1011020021112222021201 |
4 | 23101032120210310 |
5 | 144240114042122 |
6 | 5320404022244 |
7 | 605565344020 |
oct | 132116304464 |
9 | 34207488251 |
10 | 12100143412 |
11 | 514a240925 |
12 | 2418391984 |
13 | 11aab28696 |
14 | 82b049380 |
15 | 4ac452a27 |
hex | 2d1398934 |
12100143412 has 24 divisors (see below), whose sum is σ = 24763086656. Its totient is φ = 5065175808.
The previous prime is 12100143403. The next prime is 12100143413. The reversal of 12100143412 is 21434100121.
It is a self number, because there is not a number n which added to its sum of digits gives 12100143412.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12100143413) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5023773 + ... + 5026180.
Almost surely, 212100143412 is an apocalyptic number.
It is an amenable number.
12100143412 is an abundant number, since it is smaller than the sum of its proper divisors (12662943244).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12100143412 is a wasteful number, since it uses less digits than its factorization.
12100143412 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10050007 (or 10050005 counting only the distinct ones).
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 12100143412 its reverse (21434100121), we get a palindrome (33534243533).
The spelling of 12100143412 in words is "twelve billion, one hundred million, one hundred forty-three thousand, four hundred twelve".
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