121002101133130 has 384 divisors, whose sum is σ = 280355941324800. Its totient is φ = 37314844729344.

The previous prime is 121002101133061. The next prime is 121002101133143. The reversal of 121002101133130 is 31331101200121.

It is a junction number, because it is equal to n+sod(n) for n = 121002101133098 and 121002101133107.

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 34941407779 + ... + 34941411241.

It is an arithmetic number, because the mean of its divisors is an integer number (730093597200).

Almost surely, 2^{121002101133130} is an apocalyptic number.

121002101133130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

121002101133130 is an abundant number, since it is smaller than the sum of its proper divisors (159353840191670).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121002101133130 is a wasteful number, since it uses less digits than its factorization.

121002101133130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4966 (or 4959 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 121002101133130 its reverse (31331101200121), we get a palindrome (152333202333251).

The spelling of 121002101133130 in words is "one hundred twenty-one trillion, two billion, one hundred one million, one hundred thirty-three thousand, one hundred thirty".