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12100211033173 is a prime number
BaseRepresentation
bin1011000000010100110011…
…0001111100010001010101
31120211202202111211001010121
42300011030301330101111
53041222213011030143
641422432112151541
72356132336520044
oct260051461742125
946752674731117
1012100211033173
11394574174928a
1214351282385b1
1369a077b4a513
142db920a9455b
1515eb4a9437ed
hexb014cc7c455

12100211033173 has 2 divisors, whose sum is σ = 12100211033174. Its totient is φ = 12100211033172.

The previous prime is 12100211033153. The next prime is 12100211033227. The reversal of 12100211033173 is 37133011200121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9624743050129 + 2475467983044 = 3102377^2 + 1573362^2 .

It is a cyclic number.

It is not a de Polignac number, because 12100211033173 - 29 = 12100211032661 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12100211033153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050105516586 + 6050105516587.

It is an arithmetic number, because the mean of its divisors is an integer number (6050105516587).

Almost surely, 212100211033173 is an apocalyptic number.

It is an amenable number.

12100211033173 is a deficient number, since it is larger than the sum of its proper divisors (1).

12100211033173 is an equidigital number, since it uses as much as digits as its factorization.

12100211033173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 756, while the sum is 25.

Adding to 12100211033173 its reverse (37133011200121), we get a palindrome (49233222233294).

The spelling of 12100211033173 in words is "twelve trillion, one hundred billion, two hundred eleven million, thirty-three thousand, one hundred seventy-three".