Base | Representation |
---|---|
bin | 111000010110001001… |
… | …0011101001111011101 |
3 | 102120022211211120220211 |
4 | 1300230102131033131 |
5 | 3440303020321112 |
6 | 131330531212421 |
7 | 11512355023342 |
oct | 1605422351735 |
9 | 376284746824 |
10 | 121002120157 |
11 | 473535a68a6 |
12 | 1b54b447111 |
13 | b5449b7589 |
14 | 5bdc4867c9 |
15 | 3232e550a7 |
hex | 1c2c49d3dd |
121002120157 has 2 divisors, whose sum is σ = 121002120158. Its totient is φ = 121002120156.
The previous prime is 121002120139. The next prime is 121002120241. The reversal of 121002120157 is 751021200121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 67320010521 + 53682109636 = 259461^2 + 231694^2 .
It is a cyclic number.
It is not a de Polignac number, because 121002120157 - 215 = 121002087389 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121002121157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60501060078 + 60501060079.
It is an arithmetic number, because the mean of its divisors is an integer number (60501060079).
Almost surely, 2121002120157 is an apocalyptic number.
It is an amenable number.
121002120157 is a deficient number, since it is larger than the sum of its proper divisors (1).
121002120157 is an equidigital number, since it uses as much as digits as its factorization.
121002120157 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 280, while the sum is 22.
Adding to 121002120157 its reverse (751021200121), we get a palindrome (872023320278).
The spelling of 121002120157 in words is "one hundred twenty-one billion, two million, one hundred twenty thousand, one hundred fifty-seven".
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