Base | Representation |
---|---|
bin | 111000010110001001… |
… | …0110000110000110001 |
3 | 102120022211222122121011 |
4 | 1300230102300300301 |
5 | 3440303030400423 |
6 | 131330533030521 |
7 | 11512355505424 |
oct | 1605422606061 |
9 | 376284878534 |
10 | 121002200113 |
11 | 47353650983 |
12 | 1b54b485441 |
13 | b544a14aa2 |
14 | 5bdc4a79bb |
15 | 3232e6db0d |
hex | 1c2c4b0c31 |
121002200113 has 2 divisors, whose sum is σ = 121002200114. Its totient is φ = 121002200112.
The previous prime is 121002200063. The next prime is 121002200117. The reversal of 121002200113 is 311002200121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 99621034384 + 21381165729 = 315628^2 + 146223^2 .
It is a cyclic number.
It is not a de Polignac number, because 121002200113 - 233 = 112412265521 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121002200093 and 121002200102.
It is not a weakly prime, because it can be changed into another prime (121002200117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60501100056 + 60501100057.
It is an arithmetic number, because the mean of its divisors is an integer number (60501100057).
Almost surely, 2121002200113 is an apocalyptic number.
It is an amenable number.
121002200113 is a deficient number, since it is larger than the sum of its proper divisors (1).
121002200113 is an equidigital number, since it uses as much as digits as its factorization.
121002200113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 121002200113 its reverse (311002200121), we get a palindrome (432004400234).
The spelling of 121002200113 in words is "one hundred twenty-one billion, two million, two hundred thousand, one hundred thirteen".
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