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12100320031141 = 83242036023509
BaseRepresentation
bin1011000000010101001101…
…0001101111000110100101
31120211210001002220201020101
42300011103101233012211
53041222423411444031
641422451004304101
72356135132136266
oct260052321570645
946753032821211
1012100320031141
113945798226051
121435158842031
1369a0945c1764
142db93134896d
1515eb552c4361
hexb015346f1a5

12100320031141 has 8 divisors (see below), whose sum is σ = 12246615027360. Its totient is φ = 11954037130512.

The previous prime is 12100320031109. The next prime is 12100320031153. The reversal of 12100320031141 is 14113002300121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12100320031141 - 25 = 12100320031109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (18100320031141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1002906 + ... + 5020603.

It is an arithmetic number, because the mean of its divisors is an integer number (1530826878420).

Almost surely, 212100320031141 is an apocalyptic number.

It is an amenable number.

12100320031141 is a deficient number, since it is larger than the sum of its proper divisors (146294996219).

12100320031141 is an equidigital number, since it uses as much as digits as its factorization.

12100320031141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6047795.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 12100320031141 its reverse (14113002300121), we get a palindrome (26213322331262).

The spelling of 12100320031141 in words is "twelve trillion, one hundred billion, three hundred twenty million, thirty-one thousand, one hundred forty-one".

Divisors: 1 83 24203 2008849 6023509 499951247 145786988327 12100320031141