121003300100013 has 4 divisors (see below), whose sum is σ = 161337733466688. Its totient is φ = 80668866733340.

The previous prime is 121003300100009. The next prime is 121003300100077. The reversal of 121003300100013 is 310001003300121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121003300100013 - 2² = 121003300100009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121003300099965 and 121003300100001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121003300105013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20167216683333 + ... + 20167216683338.

It is an arithmetic number, because the mean of its divisors is an integer number (40334433366672).

Almost surely, 2^{121003300100013} is an apocalyptic number.

It is an amenable number.

121003300100013 is a deficient number, since it is larger than the sum of its proper divisors (40334433366675).

121003300100013 is an equidigital number, since it uses as much as digits as its factorization.

121003300100013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40334433366674.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 121003300100013 its reverse (310001003300121), we get a palindrome (431004303400134).

The spelling of 121003300100013 in words is "one hundred twenty-one trillion, three billion, three hundred million, one hundred thousand, thirteen".