Base | Representation |
---|---|
bin | 1011000000010101001111… |
… | …0111111000111010110111 |
3 | 1120211210001210201211222001 |
4 | 2300011103313320322313 |
5 | 3041222433442022243 |
6 | 41422452002520131 |
7 | 2356135313143564 |
oct | 260052367707267 |
9 | 46753053654861 |
10 | 12100330032823 |
11 | 39457a29374aa |
12 | 1435160066047 |
13 | 69a0966b4006 |
14 | 2db9327cd86b |
15 | 15eb560eca4d |
hex | b0153df8eb7 |
12100330032823 has 2 divisors, whose sum is σ = 12100330032824. Its totient is φ = 12100330032822.
The previous prime is 12100330032803. The next prime is 12100330032827. The reversal of 12100330032823 is 32823003300121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12100330032823 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12100330032791 and 12100330032800.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12100330032827) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050165016411 + 6050165016412.
It is an arithmetic number, because the mean of its divisors is an integer number (6050165016412).
Almost surely, 212100330032823 is an apocalyptic number.
12100330032823 is a deficient number, since it is larger than the sum of its proper divisors (1).
12100330032823 is an equidigital number, since it uses as much as digits as its factorization.
12100330032823 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 12100330032823 its reverse (32823003300121), we get a palindrome (44923333332944).
The spelling of 12100330032823 in words is "twelve trillion, one hundred billion, three hundred thirty million, thirty-two thousand, eight hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •