Base | Representation |
---|---|
bin | 10001100110111100000… |
… | …011001101111001001111 |
3 | 11021200022211012002012112 |
4 | 101212330003031321033 |
5 | 124311130414121002 |
6 | 2323515101054235 |
7 | 153264636561230 |
oct | 21467403157117 |
9 | 4250284162175 |
10 | 1210040770127 |
11 | 4271a2518322 |
12 | 17662025737b |
13 | 8a14c87b3c7 |
14 | 427cdc61087 |
15 | 2172144d852 |
hex | 119bc0cde4f |
1210040770127 has 16 divisors (see below), whose sum is σ = 1464288751872. Its totient is φ = 976142186880.
The previous prime is 1210040770111. The next prime is 1210040770129. The reversal of 1210040770127 is 7210770400121.
It is not a de Polignac number, because 1210040770127 - 24 = 1210040770111 is a prime.
It is a super-2 number, since 2×12100407701272 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1210040770093 and 1210040770102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1210040770129) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5528852 + ... + 5743542.
It is an arithmetic number, because the mean of its divisors is an integer number (91518046992).
Almost surely, 21210040770127 is an apocalyptic number.
1210040770127 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
1210040770127 is a deficient number, since it is larger than the sum of its proper divisors (254247981745).
1210040770127 is a wasteful number, since it uses less digits than its factorization.
1210040770127 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 262078.
The product of its (nonzero) digits is 5488, while the sum is 32.
The spelling of 1210040770127 in words is "one trillion, two hundred ten billion, forty million, seven hundred seventy thousand, one hundred twenty-seven".
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