Base | Representation |
---|---|
bin | 10001100110111111100… |
… | …101111011011100001111 |
3 | 11021200110222000111100112 |
4 | 101212333211323130033 |
5 | 124311241122414411 |
6 | 2323525022550235 |
7 | 153266260665605 |
oct | 21467745733417 |
9 | 4250428014315 |
10 | 1210100201231 |
11 | 42722301a839 |
12 | 17663813837b |
13 | 8a15bc8943c |
14 | 427d7ad1875 |
15 | 2172678cb8b |
hex | 119bf97b70f |
1210100201231 has 2 divisors, whose sum is σ = 1210100201232. Its totient is φ = 1210100201230.
The previous prime is 1210100201143. The next prime is 1210100201239. The reversal of 1210100201231 is 1321020010121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1210100201231 is a prime.
It is a super-2 number, since 2×12101002012312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1210100201239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605050100615 + 605050100616.
It is an arithmetic number, because the mean of its divisors is an integer number (605050100616).
Almost surely, 21210100201231 is an apocalyptic number.
1210100201231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1210100201231 is an equidigital number, since it uses as much as digits as its factorization.
1210100201231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 1210100201231 its reverse (1321020010121), we get a palindrome (2531120211352).
The spelling of 1210100201231 in words is "one trillion, two hundred ten billion, one hundred million, two hundred one thousand, two hundred thirty-one".
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